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Problem With A C Dictionary Code - C And C++ | Dream.In.Code


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    7 Replies - 77 Views - Last Post: Yesterday, 03:31 PM Rate Topic: -----

    #1 hadeer57 ?Icon User is offline

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    Posted Yesterday, 02:22 PM

    
#include<stdio.h> #include<string.h> #include<conio.h>  struct dictionary { char *word; char *mean; }; typedef struct dictionary Dictionary;  int main() { char i; char* enter; Dictionary a[4]; a[0].word="absolutely"; a[0].mean="spoken used to tell someone that you agree completely"; a[1].word="act"; a[1].mean="to do somthing"; a[2].word="bore"; a[2].mean="to maake someone feel bored"; a[3].word="blame"; a[3].mean="to say or think that someone is responsible for something bad"; /* char* enter; gets_s(enter)*/ gets (enter); for(i=0;i<4;i++) { if(!strcmp(enter,a[i].word)){ printf("enter the word %s\n",a[i].mean); }   }  getchar(); getchar(); }

    Mod edit - Please :code:


    Is This A Good Question/Topic? 0

    Replies To: problem with a c dictionary code

    #2 BetaWar ?Icon User is offline

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    Re: problem with a c dictionary code

    Posted Yesterday, 02:26 PM

    What exactly is the problem you are having? The more information you give us, the more easily we can help you.


    #3 hadeer57 ?Icon User is offline

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    Re: problem with a c dictionary code

    Posted Yesterday, 02:37 PM

    gets didn't identified

    This post has been edited by GunnerInc: Yesterday, 09:33 PM
    Reason for edit:: Quote be gone


    #4 redhat69 ?Icon User is offline

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    Re: problem with a c dictionary code

    Posted Yesterday, 02:55 PM

    View Posthadeer57, on 07 May 2013 - 02:22 PM, said:

    
#include<stdio.h> #include<string.h> #include<conio.h>  struct dictionary { char *word; char *mean; }; typedef struct dictionary Dictionary;  int main() { char i; char* enter; Dictionary a[4]; a[0].word="absolutely"; a[0].mean="spoken used to tell someone that you agree completely"; a[1].word="act"; a[1].mean="to do somthing"; a[2].word="bore"; a[2].mean="to maake someone feel bored"; a[3].word="blame"; a[3].mean="to say or think that someone is responsible for something bad"; /* char* enter; gets_s(enter)*/ gets (enter); for(i=0;i<4;i++) { if(!strcmp(enter,a[i].word)){ printf("enter the word %s\n",a[i].mean); }   }  getchar(); getchar(); }

    Mod edit - Please :code:/>


    What is your problem with this program?

    #5 hadeer57 ?Icon User is offline

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    Re: problem with a c dictionary code

    Posted Yesterday, 03:02 PM

    Error 1 error C2660: 'gets_s' : function does not take 1 arguments

    This post has been edited by GunnerInc: Yesterday, 09:32 PM
    Reason for edit:: Quote be gone


    #6 jjl ?Icon User is offline

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    Re: problem with a c dictionary code

    Posted Yesterday, 03:13 PM

    never use gets! gets is so dangerous that even gcc will warn you about using it. Use fgets, or something that can limit your input.


    #7 Skyla Blue ?Icon User is offline

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    Re: problem with a c dictionary code

    Posted Yesterday, 03:19 PM

    The reason you are getting that error is, gets_s takes two arguments. The first is your c string, the second is the sizeof your c string, so pass that as the second param of gets_s. I.E. gets_s(enter, sizeof(enter)); gets_s will read in n-1 characters of your string, until it reaches the newline character. Hope this helps.


    #8 JackOfAllTrades ?Icon User is online

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    Re: problem with a c dictionary code

    Posted Yesterday, 03:31 PM

    Not to mention reading into an uninitialized pointer.


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